Math, asked by priyakumarisinha2000, 11 months ago

A man's age is 3 years More than three times the age of his son.If after three years his age will be 10 years more than twice of the age of his son.Find the present age of his son?​

Answers

Answered by BrainlyVirat
30

Answer: 33 years

Step by step explanation:

Given :-

The present age of a man is 3 years more than three times the age of his son.

After 3 years, man's age will be 10 year more than twice the age of the son.

To Find: Present age of man.

Solution:

Let the son's present age be x years.  

According to the question,

Man's present age = (3x + 3) years  

(3x + 3 + 3) = 2 (x + 3) + 10  

3x + 6 = 2x + 16  

x = 10.  

Man's present age = (3x + 3)

= (3 x 10) + 3 years

= 33 years.

Hence, Man's present age is 33 years.

Answered by Anonymous
19

SOLUTION:-

Given:

•A man's age is 3 years more than three times the age of his son.

•After 3 years his age will be 10 years more than twice of the age of his son.

To find:

The present age of his son.

Explanation:

•Let the present age of his son be R years.

•Father's age be 3 + 3R years

After 3 years:

•The son's age= R+3 years.

•The father's age= 3+(3+3R) years

&

10 years more than twice of the age of his son.

According to the question:

=) 3+(3+3R)=10+2(R+3)

=) 3 + 3 +3R = 10+2(R +3)

=) 6+3R = 10 + 2R +6

=) 6 + 3R = 16 + 2R

=) 3R - 2R = 16 -6

=) R = 10 years.

Thus,

•The present age's son= 10 years.

•The present age's father= 3 + 3R

=) 3 + 3(10)

=) 3 + 30

=) 33 years.

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