Question

A man's age is 30 years more than his son. Eight years hence, father's age will be four times the age of his son.Find the present age of the son.​

Answer 1

Answer:

Step-by-step explanation

Let us consider the son's age as 'x'

Father's age = x+30

After 8 years father's age = 4x + 30

                                              x=30/4

                                              x=7.5 or 7 and half yrs old

hope it helps you

please mark this the brainliest

                                               

Answer 2

Answer:

Step-by-step explanation:

let the father's age be 4x and son's age be x

after 10years

4x + 10 = 3 *(x+ 10)

4x+10= 3x +30

4x -3x = 30-10

x= 20

therefore father's present age = 4x

=4 * 20 = 80

son's present age = x=20