Question

a man's age is 4 times the sum of the ages of three children in 8 years he will be twice the sum of their ages what is the man's age​

Answer 1

Answer :-

Age of man is 80 years.

Explanation :-

Let the sum of ages of the three children be x

Age of man = 4 times the sum of ages of the three children = 4 * x = 4x

Sum of ages of three children = x + 8 + 8 + 8 = (x + 24) years

Age of man in 8 years = (4x + 8) years

Given

Age of man in 8 years = Twice the sum of their ages in 8 years

⇒ 4x + 8 = 2(x + 24)

⇒ 4x + 8 = 2x + 48

⇒ 4x - 2x = 48 - 8

⇒ 2x = 40

⇒ x = 40/2

⇒ x = 20

i.e Sum of ages of three children = 20 years

Age of man = 4x = 4(20) = 80 years

Therefore the age of man is 80 years.

Answer 2

ANSWER:-

Given:

A man's age is 4 times the sum of the ages of three children in 8 years he will be twice the sum of their ages.

To find:

What is the man's age.

Solution:

Let the age of man= 4x.

Let the sum of three children be x years.

After 8 years age of the man= (4x+8) years.

Sum of ages three children=(x+24)years

Therefore,

=) (4x + 8) = 2(x+24)

=) 4x +8 = 2x +48

=) 4x -2x = 48 -8

=) 2x = 40

=) x = 40/2

=) x = 20 years

Hence,

The age of man's 4x= 4× 20

=) 80 years

Hope it helps ☺️