Math, asked by singhjagpalgmailcom, 1 year ago

a man's age is 6 times his son's age 10 years ago he was five times his son's age find their present ages​

Answers

Answered by Anonymous
5

\huge\text{\underline{Answer}}

Let the age of son be X years

Age of his father will be 6X years

After 10 years ago,

Son age was = ( x - 10 ) years

Father age was = ( 6x - 10 ) years

According to question

Age of father (6x - 10 )= \bold{5 (x - 10 )}

\implies \bold{6x -10 = 5x - 50}

\implies \bold{6x - 5x = -50 + 10 }

\implies \bold{x = -40 }

But age is not In negative so, plse check your question.

hence father age is 240 years.

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