Question

A man's age is seven times that of his son. In 5years he will be four times as old as his son. what are the present ages of the man and his son?​

Answer 1

Answer:

Age of the son = 5 years

Age of the man = 35 years

Step-by-step explanation:

Given :

Age of the son is x

Age of the man is 7x

After 5 years man will be four times as old as his son

To find :

Their present age

Concept :

So , we have taken age of the man as 7x .

So , the equation will form like this -:

$\boxed{\sf{(7x+5)}}$

Here taken +5 because A/Q the age has been sum 5 years .

$\:$

Now , we have taken the age of the son be x .

So , now the equation will form like this -:

$\boxed{\sf{(7x+5)=4(x+5)}}$

Taken 4 because after 5 years the age is 4 times more .

Solution :

$\leadsto\sf{(7x+5)=4(x+5)}$

$\leadsto\sf{(7x+5)=4x+20}$

$\leadsto\sf{7x-4x=20-5}$

$\leadsto\sf{3x=15}$

$\leadsto\sf{x=\dfrac{15}{3}}$

$\leadsto\sf{x=5}$

So , the age of the son is 5 years .

And to find the present age of the man do the 7 times of the age of the son .

Age of the man -:

$\leadsto\sf{7\times5\:years}$

$\leadsto\sf{35\:years}$

So , the age of the man is 35 years .