Question

A man's age is three times his son's age. ten years ago he was five times his son's age. find their present ages.

Answer 1

Solution :-

Let the man's age be 3 × y and son's age be y repectively .

⇒According to the given question :-
      
              
⇒Before ten year's , their ages were :-

              $3x - 10 = 5 ( x - 10 )$

              $3x - 10 = 5x - 50$

              $50 - 10 = 5 x - 3x$ 

              $40 = 2 x$

              $\frac{40}{2} = x$

               $20 = x$

⇒ Man's age is  3 × y = 3 × 20 = 60 yrs

⇒ Son's age is  y   = 20 yrs