Math, asked by shobas174, 5 months ago

a man's age is three times his son's age.ten years ago he was five times his son's age . find their present ages​

Answers

Answered by Anonymous
1

Step-by-step explanation:

Let Aman's son age =x

Aman's age =3x

Ten years ago, he was 5 times the age of his son.

Therefore, 3x−10=5(x−10)

3x−10=5x−50

2x=40

x=20

Aman's son is 20 yrs old

Aman is 3x=3×20=60 yrs old

Answered by nandanaMK
1

The present of his son is x = 20 years

The present of his son is x = 20 years The present age of the man is 3x = 20×3 = 60 years

Step-by-step explanation:

Let the son's age be 'x'.

The man's age would be '3x'

(3x-10)=5(x-10)

(3x-10)=5(x-10)3x-10=5x-50

(3x-10)=5(x-10)3x-10=5x-50-10+50=5x-3x

(3x-10)=5(x-10)3x-10=5x-50-10+50=5x-3x40=2x

(3x-10)=5(x-10)3x-10=5x-50-10+50=5x-3x40=2xx=40/2

(3x-10)=5(x-10)3x-10=5x-50-10+50=5x-3x40=2xx=40/2x=20

The present of his son is x = 20 years

The present of his son is x = 20 years The present age of the man is 3x = 20×3 = 60 years

Hope it helped you..!♡

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