A man's age is three times his son's age. Ten years ago his age was five times than his son's age. Find their current age
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Hi friend
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Your answer
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Let the son's present age be x.
Then , his father's present age = 3x
Now,
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According to the question,
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(3x - 10) = 5(x - 10)
=> 3x - 10 = 5x - 50
=> 5x - 3x = 50 - 10
=> 2x = 40
=> x = 40/2
=> x = 20
Therefore,
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Son's present age = x = 20 years
Father's present age = 3x = (3 × 20) years = 60 years
HOPE IT HELPS
--------------
Your answer
--------------------
Let the son's present age be x.
Then , his father's present age = 3x
Now,
--------
According to the question,
-----------------------------------------
(3x - 10) = 5(x - 10)
=> 3x - 10 = 5x - 50
=> 5x - 3x = 50 - 10
=> 2x = 40
=> x = 40/2
=> x = 20
Therefore,
-----------------
Son's present age = x = 20 years
Father's present age = 3x = (3 × 20) years = 60 years
HOPE IT HELPS
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