Question

a man's age is three times that of his son and in 12 years he will be twice as old as his son would be what are their present age​

Answer 1

Answer:

son's present age=x=12 years

father's present age=3x=3*12=36 years

Step-by-step explanation:

let the age of son be x

then father's age= 3x

in 12 years

son's age= x+12

father's age= 3x+12

A.T.Q

2(x+12)=3x+12

2x+24=3x+12

2x-3x=12-24

-x=-12

- cut

x=12

son's age and father's age is given in answer

Answer 2

★ Provided that:

• A man's age is three times that of his son.

• In 12 years he will be twice as old as his son

★ We have to find out:

• Present ages of man and son.

★ Assuming that,

• Present age of son as y

★ Let's solve:

• Father's age would be = y × 3 = 3y

After 12 years,

• Age of son would be y + 7
• Age of father would be 3y + 7

Ages are twice,

• 2 (y + 12)

Hence, equation formed:

• 2 (y + 12) = 3y + 12

★Opening bracket★

• 2 × (y + 12) = 3y + 12
• 2y + 24 = 3y + 12

★ Changing the sides ★

• 2x - 3x = 12 - 24
• -x = -12

★ Negative signs would be cancelled ★

• x = 12

★ Hence, age of son is 12 years ★

★ Father's age:

• 3y = 3 × 12 = 36

★ Hence, father's age is 36 years ★