A man's age is three times the sum of ages of his two sons. After 5 years, age will be twice the sum of the ages of his sons. Find the age of man.
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A man's age is three times the sum of ages of his two sons. After 5 years, age will be twice the sum of the ages of his sons. Find the age of man.
solution.
- Let the sum of ages of two sons be x years
- Age of man = 3xyears
- After 5 years age of the man =(3x+5)years
Sum of ages of two sons =(x+10)years
Given,
- (3x+5)=2(x+10)
- ⇒ (3x+5)=2x+20
- ⇒ x=15
Hence 3x=3(15)=45
∴ Present age of father is 45years.
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Question
A man's age is three times the sum of ages of his two sons. After 5 years, age will be twice the sum of the ages of his sons. Find the age of man.
solution.
Let the sum of ages of two sons be x years
Age of man = 3xyears
After 5 years age of the man =(3x+5)years
Sum of ages of two sons =(x+10)years
Given,
(3x+5)=2(x+10)
⇒ (3x+5)=2x+20
⇒ x=15
Hence 3x=3(15)=45
∴ Present age of father is 45years.
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