• A man's age is three times the sum of ages of his two sons. After 5 years, his age will be twice the sum of ages of his two sons. Find the age of the man.
Answers
Given : A man's age is three times the sum of ages of his two sons.
After 5 years, his age will be twice the sum of ages of his two sons.
To Find : Age of the man.
Solution:
Age of Son1 = A Years
Age of Son2 = B Years
Age of Man = M Years
man's age is three times the sum of ages of his two sons.
=> M = 3( A + B)
After 5 years Age of Son1 = A + 5 Years
Age of Son2 = B + 5 Years
Age of Man = M + 5 Years
After 5 years, his age will be twice the sum of ages of his two sons.
=> (M + 5) = 2(A + 5 + B + 5)
=> M + 5 = 2(A + B) + 20
=> M = 2(A + B) + 15
3( A + B) = 2(A + B) + 15
=> (A + B) = 15
M = 3( A + B)
=> M = 3(15)
=> M = 45
Age of Man = 45 Years
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