A man's age is three times the sum of the ages of his two sons. Afterv5 years, his age will be twice the sum of ages of his two sons. Find the age of the man.
Answers
Step-by-step explanation:
Let the sum of ages of two sons be x years Age of man = 3x years After 5 years age of the man = (3x + 5) years Sum of ages of two sons = (x + 10) years Given, (3x + 5) = 2(x + 10) ⇒ (3x + 5) = 2x + 20 ⇒ x = 15 Hence 3x = 3(15) = 45 Thus the age of the man(father) is 45 years.
Answer:
★ As per the given question, A man's age is three times the sum of the ages of his two sons. After 5 years, his age will be twice the sum of ages of his two sons. To find what is the age of the man.
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★ Let us assume 'x' as age of man and 'y' be age of two sons.
★ Let 'x + 5' be the man's age after 5 years, The sum of two childrens age be 2 (y + 10) [After 5 years].
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Calculations:
→ x + 5 = 2 (y + 10) = 2y + 20
→ 3y + 5 = 2y + 20
→ y = x + y
→ y = 15
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→ x = (3 × 15)
→ x = 45
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Therefore,
- The age of man is (x = 45 years).
- The age of both children is (y = 15 years).