Math, asked by shivampandeyup555, 9 months ago

a man's present age is 8 times his son's age . after two years,his age
will be six times his son's age. What are their present age.​

Answers

Answered by suveda34
0

Step-by-step explanation:

sons age = 5

fathers age = 5 × 8 = 40

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Answered by VishnuPriya2801
6

Answer:

5 years ; 40 years.

Step-by-step explanation:

Let, the Son's age be "x" and father's age be "y".

given that the father's age = 8x

Hence , y = 8x.

After two years son's age = x +2

father's age = 6(X+2)

y = 6x + 12

According to the problem,

8x +2 = 6x + 12

8x - 6x = 12 - 2

2x = 10

X = 10/2

X = 5.

Therefore, age of son = 5 and father's = 8(5) = 40 years.

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