Math, asked by venky15879, 1 year ago

A man's present age is 8 times his son's ages. 12 years later he will be 28 years old than his son .what are the present ages of the father and son

Answers

Answered by AGClash1236
1
let the age of father be 8x and son be x.
then, 12 yrs later, their age be (8x +12) and (x+12).
so, on condition,
(8x +12)-(x+12) = 28
8x +12 -x -12 = 28
7x = 28
x = 4.

therefore, the present age of father is 32 yrs and son is 4 yrs.
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