Question

a man's present age is 8 times more than his son. after 10 years, he will be thrice the age of his son how old is son at present? ​

Answer 1

Step-by-step explanation:

Let p = man’s present age and s = son’s age.

p = 8 * s

p+2 = 6* (s+2)

Now we use simultaneous equations to solve for p and s.

(8*s) + 2 = 6*(s+2) // Here I replaced p with 8*s

8s + 2 = 6s +12 // Expand bracket

2s = 10

s = 5

Therefore, by simple substitution we see that p = 40

The man’s present age is 40, the son’s present age is 5.

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Answer 2

Let p = man’s present age and s = son’s age.

p = 8 × s

p + 2 = 6 × (s+2)

Now we use simultaneous equations to solve for p and s.

(8 × s) + 2 = 6 × (s+2) // Here I replaced p with 8 × s

8s + 2 = 6s + 12 // Expand bracket

2s = 10

s = 5

Therefore, by simple substitution we see that p = 40

The man’s present age is 40, the son’s present age is 5.

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