Question

a man's present age is 8 times more than his son after 10 years he will be twice the age of his son how old is son at present
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Answer 1

Answer:

Present age of son 1 year 2 months.

Step-by-step explanation:

Given :-

A man's present age is 8 times more than his son.

After 10 years, he will be twice the age of his son.

To find :-

Present age of son.

Solution  :-

Consider,

The present age of son = x years

★ A man's present age is 8 times more than his son.

Then,

The present age of the man = 8x years

After 10 years,

Son's age = (x+10) years

Man's age = (8x+10) years

★After 10 years, he will be twice the age of his son.

According to the question,

8x+10 = 2(x+10)

→ 8x + 10 = 2x + 20

→ 8x-2x = 20-10

→ 6x = 10

→ x = 5/3

→ x = 1 year 2 months

★The Present age of son = 1 year 2 months.

★ Present age of man = 8 × 5/3 = 40/3 = 13 years 1 month.

Answer 2

Given :

• A man's present age is 8 times more than his son after 10 years he will be twice the age of his son.

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Find :

• What is the present age of son.

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Concept :

• We can easily solve this question if we follow the question and understand it clearly.

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• Write step by step to make the answer perfectly.

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• Let "x" be the present age of son and "8x" be the present age of the man (Their present ages).

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• Let "(x + 10)" be the age of son, let "(8x + 10)" be the age of man (After 10 years).

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Calculations :

→ 8x + 10 = 2(x + 10)

→ 8x + 10 = 2x + 20

→ 8x - 2x = 20 - 10

→ 6x = 10

→ x = 10/6

→ x = 5/3

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Finding their present ages :

→ Present age of Son = 1 year 2 months

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→ Present age of Man = 8 × 5/3

→ Present age of Man = 40/3

→ Present age of man = 13 years 1 month