A man's present age is two fifth of the age of his mother.After 8 years , he will be one-half of the age of his mother at that time. How old is the mother at present?
Answers
Answer:
Let person's age be X years.. and mother's age is 2.5 times, i.e., 2.5X...... After 8 years, he will be one-half of the age of mother... this means...X+ 8 = 1/2 (2.5 X + 8).... 2(X+8)=2.5X + 8.....2X + 16= 2.5X + 8......0.5X=8....X=16 years....Present age of Mother = 2.5X = 2.5 × 16= 40 years.....
Answer:
Answer:maths
Answer:mathsStep-by-step explanation:
Answer:mathsStep-by-step explanation:the correct answer is 40 years..
Answer:mathsStep-by-step explanation:the correct answer is 40 years..solution:
Answer:mathsStep-by-step explanation:the correct answer is 40 years..solution:P = 2/5 M
Answer:mathsStep-by-step explanation:the correct answer is 40 years..solution:P = 2/5 Mafter 8 years
Answer:mathsStep-by-step explanation:the correct answer is 40 years..solution:P = 2/5 Mafter 8 yearsP+8 = 1/2(M+8)
Answer:mathsStep-by-step explanation:the correct answer is 40 years..solution:P = 2/5 Mafter 8 yearsP+8 = 1/2(M+8)substitute P = 2/5 M
Answer:mathsStep-by-step explanation:the correct answer is 40 years..solution:P = 2/5 Mafter 8 yearsP+8 = 1/2(M+8)substitute P = 2/5 M2/5 M = 1/2 M + 4
Answer:mathsStep-by-step explanation:the correct answer is 40 years..solution:P = 2/5 Mafter 8 yearsP+8 = 1/2(M+8)substitute P = 2/5 M2/5 M = 1/2 M + 4hence M = 40 years