A man's weight on the surface of the earth is 95Kg. How much would be
weight in a rocket at a distance of 40000 km from the earth?
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Answer:
(a) R1 = 500ohm, R2 = 1000ohm
As per given figure,
R = R1 + R2 = 500 + 1000 = 1500ohm.
(b) R1 = 2ohm, R2 = 2ohm
As per given figure,
1/R = 1/R1 + 1/R2
1/R = 1/2 + 1/2
R = 1ohm
(c) R1=4ohm, R2 = 4ohm, R3 = 3ohm
As per given figure,
1/R=1/R1 + 1/R2
1/R = 1/4 + 1/4
R = 2ohm
Total resistance =R + R3
= 2 + 3 = 5ohm
Explanation:
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