Question

A man's weight when taken at the pole is 600N . will his weight remain the same when measured at the equator ? will there be an increase or decrease in his weight ? Explain​

Answer 1

Increase

Explanation:

At the poles: distance from the centre of earth is lesser than that from equator. As g is inversely proportional to the distance, and distance is decreased, it must increase.

Mathematically:

Force = mg = Gmm₁/r²

g = Gm₁/r²

At the equator, G = 6.67430 x 10⁻¹¹ & m(mass of earth) = 5.972 × 10^24 kg

r(radius of earth, from the view of eq.) = 6378 km. Based on these values(or their approximations:

g = 9.78 m/s²

But at the poles: radius = 6357 km, thus,

radius = 6357 km, thus,at poles, g' = 9.832 m/s (on calculations)

Answer 2

$answer$

Increase

Explanation:

At the poles: distance from the centre of earth is lesser than that from equator. As g is inversely proportional to the distance, and distance is decreased, it must increase.

Mathematically:

Force = mg = Gmm₁/r²

g = Gm₁/r²

At the equator, G = 6.67430 x 10⁻¹¹ & m(mass of earth) = 5.972 × 10^24 kg

r(radius of earth, from the view of eq.) = 6378 km. Based on these values(or their approximations:

g = 9.78 m/s²

But at the poles: radius = 6357 km, thus,

radius = 6357 km, thus,at poles, g' = 9.832 m/s (on calculations)