Question

A man's weight when taken at the pole is 600N . will his weight remain the same when measured at the equator ? will there be an increase or decrease in his weight ? Explain

Answer 1

We know that gravity at pole is slightly higher than gravity at equator.

Value of g at pole is 10 m/s^2 whereas at equator, it is 9.8 m/s^2.

So weight of the person will be slightly less at equator than at pole.
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If you want how much less,

Weight at pole = 600N

mass = W/g' = 600/10 = 60kg

Weight at equator = mg = 60×9.8 = 588N

So his weight will be 12N less at equator than at pole.

Answer 2

Answer:

Increase

Explanation:

At the poles: distance from the centre of earth is lesser than that from equator. As g is inversely proportional to the distance, and distance is decreased, it must increase.  

         Mathematically:

Force = mg = Gmm₁/r²

               g = Gm₁/r²

At the equator, G = 6.67430 x 10⁻¹¹  & m(mass of earth) = 5.972 × 10^24 kg

r(radius of earth, from the view of eq.) = 6378 km. Based on these values(or their approximations:

       g = 9.78 m/s²

But at the poles: radius = 6357 km,  thus,

at poles, g' = 9.832 m/s   (on calculations)