Question

A man saved 30,000 in 8 years. Each year he
saved 500 more than he saved in the
preceding year. Find his savings in the first
year.
​

Answer 1

its 2575

(500 added in first time)

i think so

but i am not sure

Answer 2

rs 2000

Step-by-step explanation:

let the money saved in first year be a

given S8 = 30000 , d=500

Sn= N/2 (2a + (n-1)d)

8/2 (2a + 7(500) )

4(2a + 3500) = 30000

8a + 14000=30000

8a = 30000-14000

a=16000/8

a= 2000

answer amount of money saved in first year is rs 2000

confirmation - 2000+2500+3000+3500+4000+4500+5000+5500 = 30000

hence confirmed