Question

a man saved rs.16500 in 10 years. in each year after the 1st he saved rs. 100 more than he did in the preceding year. how much did he save in the 1st year?

Answer 1

let x be savings of this year ,then x+100 will be savings of next year and x+200 will be savins of after 2 years  and soon .He saves for 10 years.

x+x+100+x+200+..........x+900=16500

10x=12000

x=1200 which is savings of 1st year

Answer 2

Answer:

A man saved ₹ 1200 in first year.

Step-by-step explanation:

Given :  

In 10 years a man saved, S10 = ₹16500

In each year after the first he saved, d = 100

Here , number of years, n = 10

Let 'a' be the first year.

By using the formula ,Sum of nth terms , Sn = n/2 [2a + (n – 1) d]

S10= 10/2 [2a + (10 – 1) 100]

16500 = 5 [2a + 9 × 100]

16500/5 = 2a + 900

3300 = 2a + 900

2a = 3300 – 900

2a = 2400

a = 2400/2

a = 1200

Hence, a man saved ₹ 1200 in first year.

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