A man saved Rs 16500 in 10 years. In each year after the first saving he saved Rs 100 more than the preceding year. Here …..
(a) a = Rs 16500, d = Rs 100
(b) S = Rs 16500, d = Rs 100
(c) S = Rs 16500, a = Rs 100
(d) tn = Rs 16500, d = Rs 100
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Correct option is
D
Rs. 1200
Sn=16500,n=10,d=100
Sn=2n[2a+(n−1)d]
∴16500=210[2a+(10−1)100]
16500=5[2a+900]
16500=10a+4500
10a=12000
∴a=1200
Hence he saves Rs. 1200 in first year.
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