Question

A man saved rs 16500 in ten years . in each year after he saved rs 100 more than he did in receding year . how much did he save in the first year ?​

Answer 1

Answer:

1640 save in first year

Answer 2

Answer:

Here, we are given that the total saving of a man is Rs 16500 and every year he saved Rs 100 more than the previous year.

So, let us take the first installment as a.

Second installment = a+100

Third installment = a+100+100

So, these installments will form an A.P. with the common difference (d) = 100

The sum of his savings every year

Number of years (n) = 10

So, to find the first installment, we use the following formula for the sum of n terms of an A.P.,

Sn=n/2[2a+(n-1)d]

Where; a = first term for the given A.P.

d = common difference of the given A.P.

n = number of terms

So, using the formula for n = 10, we get,

S10=10/2[2a+(10-1)100]

16500-4500=10a

Further solving for a,

10a=12000

a=1200

Therefore, man saved RS 1200 in the first year.