Question

a man saved Rs.66000 in 20 years .In each succeeding year after the first year he saved Rs.200 more than what he saved in the previous year .How much did he saved in the first year.​

Answer 1

Answer:

62200

Step-by-step explanation:

See this is a clear case of Arithmetic Progression(A.P). whose first term we don't know and we need to find it out and the common difference is given to us is 200.

$general \: term = a + (n - 1)d$

So,

$a + (20 - 1) \times 200 = 66000$

From here we get,

$a = 66000 - 3800$

$=> a = 62200$

this is the answer to your question i.e the savings in the first year. ENJOY!☺