Question

A man saved rupees 24000 in 10 years . In each year after the first year, he saved Rs 200 more than the preceding year. Find his savings in the first year

Answer 1

please see answer in the pic given below

mark it as a brainliest answer

Answer 2

Answer:

The answer is RS.1,500

Step-by-step explanation:

Given:

Sn=24,000; n=10; d=200

As we know that: Sn=n/2 [2a+(n-1)(d)]

24,000=10/2 [2a+(10-1)(200)]

24,000=5(2a+1800)

24,000=10a+9000

24,000-9000=10a

15000/10=a

a=1500

hence, he saves Rs.1,500 in first year