A man saved rupees 24000 in 10 years . In each year after the first year, he saved Rs 200 more than the preceding year. Find his savings in the first year
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Answer:
The answer is RS.1,500
Step-by-step explanation:
Given:
Sn=24,000; n=10; d=200
As we know that: Sn=n/2 [2a+(n-1)(d)]
24,000=10/2 [2a+(10-1)(200)]
24,000=5(2a+1800)
24,000=10a+9000
24,000-9000=10a
15000/10=a
a=1500
hence, he saves Rs.1,500 in first year
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