Question

- A man saves *32 during the first year. * 36 in the second year and in this way he increase his savings by
(Ans.n=5 year
* 4 every year. Find in what time his savings will be * 200.​

Answer 1

He will complete his savings on 19 years

Answer 2

Step-by-step explanation:

Given- If a person increase by 4 per year than d=4

Sn=200 , a=32 , n=?

Sn=n/2(2a+(n-1)d)

200=n/2(64+4n-4)

200=n(30+2n)

2n^2+30n-200=0

D=b^2-4ac

D=2500

n= -b/2a+-under root d/2a

n = -30/4-50/4 and n= -30/4+50/4

n = -80/4 and n = 20/4

n = -40 and n= 5

Time can never be in negetive.

Therefore, n=5 , person's saving would be 200 in 5 years