Question

A man saves 320 in the month of January, * 360 in the
month of February, 400 in the month of March. If he
continues his saving in the same way:
(a) Find his saving in the month of November in the same
year.
(b) Find his saving in the month of July in the same year.​

Answer 1

Given:

• A man saves ₹320 in January.
• He saves ₹360 in February.
• He saves ₹400 in March.

_____________________

To find:

• His saving in the month of November in the same year.
• His saving in the month of July in the same year.

_____________________

Solution:

We are given that,

$\bigstar {\sf {\purple {A\ man\ saves\ ₹320\ in\ January.}}}$

$\bigstar {\sf {\purple {He\ saves\ ₹360\ in\ February.}}}$

$\bigstar {\sf {\purple {He\ saves\ ₹400\ in\ March.}}}$

Here, we can see that this is a simple addition series, wherein as the month keeps on increasing, the amount of money saved also keeps on increases.

That is,

Month + 1 = Next month

Previous month's savings + ₹40 = Next month's savings

So,

In January, it is ₹320.

In February, it is ₹360. ₹(320+40)

In March, it is ₹400. ₹(360+40)

In June, it will be ₹440. ₹(400+40)

In July, it will be ₹480. ₹(440+40)

In August, it will be ₹520. ₹(480+40)

In September, it will be ₹560. ₹(520+40)

In October, it will be ₹600. ₹(560+40)

In November, it will be ₹640. ₹(600+40)

In December, it will be ₹680. ₹(640+40)

_____________________

Final answer:

$\boxed {\sf {\green {The\ man\ will\ save\ Rs.\ 640\ in\ November.}}}$

$\boxed {\sf {\orange {The\ man\ will\ save\ Rs.\ 480\ in\ July.}}}$