Math, asked by bhanupratapsingh0922, 9 months ago

. A man saves 33,000 every year and
invests it at the end of the year at 10%
compound interest. Calculate the total
amount of his savings at the end of the third
year.

urgent​

Answers

Answered by annamaryjoseph977
1

Answer:

p=33000

r=10

t=3

CI FOR 1ST YEAR=3000*10*1/100

A=300

P FOR 2ND YEAR=3000+3300=RS6300

CI FOR 2ND YEAR =6300*10*1/100

=630

A=6300+630

=6930

P FOR 3RD YEAR= 3000+6300

= Rs 9930

Step-by-step explanation:


bhanupratapsingh0922: thank you
annamaryjoseph977: always
Answered by Anonymous
8

Answer:

Rs. 10230

Step-by-step explanation:

Given,

P= Rs 33000

R=10%

T= 3 years

Compound interest for first year

= (33000x10x1)/ 100 = 3300

Amount= 3000+3300

= 6300

P for 2nd year = 3000+6300=9300

Compound interest for 2nd year

= (9300x10x1) / 100 = 930

Amount = 6300+930 = 7230

P for 3rd year = 3000 + 7230 = Rs.10230


bhanupratapsingh0922: the answer is wrong sorry upper is correct
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