. A man saves 33,000 every year and
invests it at the end of the year at 10%
compound interest. Calculate the total
amount of his savings at the end of the third
year.
urgent
Answers
Answered by
1
Answer:
p=33000
r=10
t=3
CI FOR 1ST YEAR=3000*10*1/100
A=300
P FOR 2ND YEAR=3000+3300=RS6300
CI FOR 2ND YEAR =6300*10*1/100
=630
A=6300+630
=6930
P FOR 3RD YEAR= 3000+6300
= Rs 9930
Step-by-step explanation:
bhanupratapsingh0922:
thank you
Answered by
8
Answer:
Rs. 10230
Step-by-step explanation:
Given,
P= Rs 33000
R=10%
T= 3 years
Compound interest for first year
= (33000x10x1)/ 100 = 3300
Amount= 3000+3300
= 6300
P for 2nd year = 3000+6300=9300
Compound interest for 2nd year
= (9300x10x1) / 100 = 930
Amount = 6300+930 = 7230
P for 3rd year = 3000 + 7230 = Rs.10230
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