Math, asked by muskaan8250, 1 year ago

A man saves Rs. 200 in each of the first three months of his service. In each of the subsequent months his saving increases by Rs. 40 more than the saving of immediately previous month. His total saving from the start of service will be Rs. 11040 after ?
A) 19 months
B) 21 months
C) 18 months
D) 20 months

Answers

Answered by rudra2833
63



Total savings = 200 + 200 + 200 + 240 + 280 + ... to n months = 11040
= 120 + 80 + 160 + 40 + 200 + 240 + ....n terms
= 40 + 80 + 120 + 160 + 200 + 240 + ...n terms
= n/2[2a + (n-1)d] + 80 + 40 = 11040
= n/2[240 + (n-1)40] = 10920
= n[6+n-1] = 546
= n[n+5] = 546
n = 21

Thx for giving me a chance
Answered by harshitasuri2004
3

Answer:

21 is the answer........

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