Question

A man saves rupees 32 during the first year rupees 36 in 2nd year and in this way he increased his saving by rs 4 every year find in what time his saving will be rs 200

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

5 years

Step-by-step explanation:

Savings every year are in an Arithmetic Progression (AP)

32, 36, 40, .....

First term, a = 32

Difference, d = 4

Let the total no. of terms for total savings = 200 be 'n'

Sum of n terms of an AP, S = n/2(2a + (n-1)d)

200 = n/2(64 + (n-1)4)

solving this you will get the quadratic equation

n² + 15n - 100 = 0

n² + 20n - 5n - 100 = 0

n(n + 20) - 5(n + 20) = 0

(n - 5)(n +20) = 100

n = 5 or -20

No. of terms can't be -ve

So, n = 5

Therefore, it will take 5 years for the savings to be Rs. 200

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