a man say to his son seven years ago I was seven times as old as you were and three years hence I shall be three times as old as you find their ages
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Answer:
mans age is 42 years and sons age is 12 years respectively
Step-by-step explanation:
let mans age be x
let sons age be y
therefore, first case
x-7 = 7(y-7)
x-7y+42=0
second case,
x+3 = 3(y+3)
x-3y-6=0
by equating both the cases,
we get that y is 12 and x is 42
therefore their ages are 42 and 12 respectively.
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