A man sees the top of a tower in the mirror, which is at a distance of 80.4 metres from Tower the mirror is the ground facing upwards. The man is 0.6 away from the mirror and his height is 1.8. How tall is the tower?
Answers
The height of the tower is 241.2 m
Distance = 80.4m (Given)
Distance of the man = 0.6m (Given)
Height of the man = 1.8m (Given)
Let the height of the tower be = AB
Let the distance of the man from the mirror = CD
Let the distance of the man from the tower = CB
Let the distance of the eye level of the man from the ground = ED
Since,
ΔCDE ~ ΔABC ( By AAA Criterion )
Thus,
CD / CB = ED / AB
= 0.6 / 80.4 = 1.8 / AB
= AB = (1.8 x 80.4) / 0.6
= 241.2
Therefore, the height of the tower is 241.2 m
Given :
• A man sees the top of a tower in a mirror which is at a distance of 80.4 metres from the tower. The mirror is on the ground facing upwards. The man is 0.6 metres away from the mirror and his height is 1.8 metres.
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Find :
• How tall is the tower?
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Calculations :
★ Let "x" be the height of the tower.
ㅤㅤ
→ x = 0.6/80.4
→ x = 1.8/x
ㅤㅤ
→ x = (1.8 * 80.4)/0.6
→ x = 144.72/0.6
→ x = 241.2 m
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Therefore ,
★ 241.2 meter is the height of the tower.