A man sees the top of the tower in a mirror which is at a distance of 87. 6m from the tower. The mirror is on the ground facing upward. The man is 0. 4m away from the mirror, and the distance of his eye level from the ground is 1.5m. How tall is tower.? (Man, mirror and tower lie on same plane or along a straight line).
Answers
Answer:
328.5 m
Step-by-step explanation:
Given A man sees the top of the tower in a mirror which is at a distance of 87. 6 m from the tower. The mirror is on the ground facing upward. The man is 0. 4 m away from the mirror, and the distance of his eye level from the ground is 1.5 m. How tall is tower.? (Man, mirror and tower lie on same plane or along a straight line).
Now in Δ PAB and Δ PQR
APB = QPR (angle of reflection)
ABP = QRP (90 degree)
Therefore ΔPAB ΔPQR
PB/PR = AB/QR
0.4 / 87.6 = 1.5 / QR
QR = 1.5 x 87.6 / 0.4
QR = 328.5 m
Therefore height of the tower is 328.5 m
Answer:
328.5 m
Step-by-step explanation:
Given A man sees the top of the tower in a mirror which is at a distance of 87. 6 m from the tower. The mirror is on the ground facing upward. The man is 0. 4 m away from the mirror, and the distance of his eye level from the ground is 1.5 m. How tall is tower.? (Man, mirror and tower lie on same plane or along a straight line).
Now in Δ PAB and Δ PQR
APB = QPR (angle of reflection)
ABP = QRP (90 degree)
Therefore ΔPAB ΔPQR
PB/PR = AB/QR
0.4 / 87.6 = 1.5 / QR
QR = 1.5 x 87.6 / 0.4
QR = 328.5 m
Therefore height of the tower is 328.5 m