A man sell a painting for Rs 150000 at a 20% loss. How much did he buy it
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Answer:
Step-by-step explanation:
Let Rs. x be the amount at which the art dealer bought the painting
Now it is given that the art dealer sold the painting at a loss of 20%
So selling price
\displaystyle \sf{ = x - \frac{20x}{100} }=x−
100
20x
\displaystyle \sf{ = x - \frac{x}{5} }=x−
5
x
\displaystyle \sf{ = \frac{4x}{5} }=
5
4x
So by the given condition
\displaystyle \sf{ \frac{4x}{5} = 150000 }
5
4x
=150000
\displaystyle \sf{ \implies \: x = 150000 \times \frac{5}{4} }
⟹x=150000×
4
5
\displaystyle \sf{ \implies \: x = 150000 \times 1.25 }⟹x=150000×1.25
∴ x = 187500
So the amount at which the art dealer bought the painting = Rs. 187500
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