Math, asked by 256indrani, 1 year ago

A man sells 10 oranges for rupee 1 and gains 50%.how many for a rupee had he bought them?

Answers

Answered by ayeshakhan40
0

But what profit or losse


256indrani: 50% profit
256indrani: I guess the answer is 15
Answered by amitnrw
3

Answer:

He bought 15 Oranges for a Rupee

Step-by-step explanation:

Sells 10 oranges for Rs 1

1 orange Sold = 1/10 Rs = 10 Paise

Let say cost price of 1 orange = C Paise

Profit = Selling Price - Cost Price

Profit = 10 - C  Paise

Profit % = (Profit / Cost Price ) * 100

=> 50 = ((10 - C)/C ) * 100

=> C = (10 - C) * 2

=> C = 20 - 2C

=> 3C = 20

=> C = 20/3

Cost Price of 1 orange = 20/3 Paise

1 Rs = 100 Paise

in 20/3 Paise Orange bought = 1

in 1 Paise Orange bought = 1/(20/3) = 3/20

in 100 Paise Orange bought = (3/20) * 100

= 3 * 5

= 15

He bought 15 Oranges for a Rupee


256indrani: Beautiful explanation
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