Question

A man sells 3 articles first at a profit of 20%, second at a loss of 10% and the third at 25% loss. During the whole transaction he bear's a loss of rs 60. Find the c.P of each article if their s.P are same.

Answer 1

Concept:

Selling price = Cost price ±( profit / loss)

Given:

3 articles:

first at a profit of 20%, second at a loss of 10% and the third at 25% loss.

Loss = Rs. 60

Find:

Cost price of all the articles.

Step-by-step explanation:

Let the selling price be x.

For good 1:

CP + 20 % CP = x

CP = x / 1.2

For good 2:

CP = x / 0.9

For good 3:

CP = x / 0.75

Now ATQ:

3 x - x/1.2 - x/0.9 - x/0.75 = - 60

3 x - 59/18 x = -60

5 / 18 x = 60

5 x = 108

x = 21.6

CP of good 1 = 21.6 / 1.2 = 18

CP for good 2 = 21.6 / 0.9 = 24

CP for good 3 = 21.6 / 0.75 = 28.8.

Therefore, the CP of good 1 is Rs.18, for good 2 is Rs.24 and for good 3 is Rs.28.8.

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Answer 2

Answer:

CP of good 1 = 21.6 / 1.2 = 18

CP for good 2 = 21.6 / 0.9 = 24

CP for good 3 = 21.6 / 0.75 = 28.8.

Step-by-step explanation:

Profit $=(\mathrm{SP}-\mathrm{CP})$

Profit $\%=( Profit / CP ) \times 100$

LOSS  $=(\mathrm{CP}-\mathrm{SP})$

LOSS $\%=( LOSS / C P) \times 100$

If the selling price be x.

For good 1:

CP + 20 % CP = x

CP = x / 1.2

For good 2:

CP = x / 0.9

For good 3:

CP = x / 0.75

Now ATQ:

3 x - x/1.2 - x/0.9 - x/0.75 = - 60

3 x - 59/18 x = -60

5 / 18 x = 60

5 x = 108

x = 21.6

CP of good 1 = 21.6 / 1.2 = 18

CP for good 2 = 21.6 / 0.9 = 24

CP for good 3 = 21.6 / 0.75 = 28.8.

If given S.P = Rs. 330 Profit = 10% C.P = Rs. X C.P = S.P - 10% of C.P Find C.P:

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