Question

A man sells a car to his friend at 10% loss. if the friend sells it for Rs. 54000 and gens 20%, then the original C.P of the car was_______. A) Rs. 45000 B) Rs. 37000 C) Rs. 50000 D) Rs. 60000

Answer 1

let the C.p. of his friend be A.
A + Ax20/100 =54000
120/100A        = 54000
A                     = 54000x100/120
                         =45000
Let the original Cp of the car be c.
c-cx10/100 = 45000
90/100 c     =45000
c                  = 45000x100/90
                   = 50000
ans:) C option(50000)
 

Answer 2

Answer:

The original C.P of the car was is Rs.50000

Step-by-step explanation:

Let the original price be x

Loss% = 10%

loss = 10%x = 0.1 x

SP = CP-Loss = x-0.1 x = 0.9 x

Now we are given that the friend sells it for Rs. 54000 and gains 20%

So, CP = 0.9x

Profit% = 20%

Profit = $\frac{20}{100} \times 0.9 x =\frac{9}{50}x$

SP = CP+Profit = $0.9x+\frac{9}{50}x=\frac{54}{50}x$

We are given that SP = Rs.5400

So, $\frac{54}{50}x=54000$

$x=\frac{54000 \times 50}{54}$

$x=50000$

Hence the original C.P of the car was is Rs.50000