Question

A man sells a handset for * 5600 and incurs a loss of 20%. He sells a second handset at a
profit of 50%. If on the whole transaction, he neither gains nor loses, find the cost price
of the second handset.
A man bought two bikes for * 1,85,600. By selling one at a loss of 15% and the other
at a profit of 12%, he found that the selling price of the first bike is more than the
second bike by 10,000. Find the CP of each.​

Answer 1

Answer:

I cant help u tht much but try to find the percent in ratio terms then divide it hope this helps u hv a great day

Answer 2

Hope it helps you

Answer:2800 rs

Step-by-step explanation:Let the cost price of first handset be 'x' then

SP= Rs 56.00

loss = 20%

loss=  

CP

CP−SP

​  

×100

0.20=  

x

x−5600

​  

 

x

5600

​  

=1−0.20=0.80

x=  

0.80

560000

​  

=7,000 Rs

Now loss in this deal = 7,000- 5600= 1400 Rs

if he sells second handset in profit equal to loss in first handset then

profit % =  

CP

SP−CP

​  

×100

50=  

x

1400

​  

×100

x=  

50

1400×100

​  

=2800Rs