Math, asked by kirti4272, 10 months ago

a man sells two article first at 15%loss and second at 19%profit if during the transaction he bears a loss of rupees 90.if he sell both article at same price then find the cost price of second article. ​

Answers

Answered by Anonymous
17

comment for any doubt you have

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Answered by amitnrw
3

Cost Price of 2nd article = Rs 4500

Step-by-step explanation:

Cost Price of article sold at Loss = L

Cost price of article sold at Profit  = P

15%loss  = (15/100)L = 0.15L

Selling Price = L - 0.15L = 0.85L

19% profit = (19/100)P  = 0.19P

Selling Price = P + 0.19P = 1.19P

0.85L = 1.19P

=> L = 1.4P

if during the transaction he bears a loss of rupees 90

=> 0.15L  - 0.19P  = 90

=> 0.15(1.4P) - 0.19P = 90

=> 0.21P - 0.19P = 90

=> 0.02P = 90

=> P = 4500

Cost Price of 2nd article = Rs 4500

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