Question

A man sells two horses for Rs 1710. The cost price of first is equal to the selling price of second horse.If the first is sold at 10% loss and the second at 25% gain, What is his total gain or loss (in rupees)?

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Total gain = 11.76%

Step-by-step explanation:

Selling price of two horses = Rs 1710 ---(1)

Let selling price of first horse = x,

Selling price of the second horse = 1710 - x ,

i) cost price (c.p) = second price of the second horse = (1710-x)

loss(l) = 10%

$s.p = c.p\left(\frac{100-l}{100}\right)$

$\implies x = (1710-x)\left(\frac{100-10}{100}\right)$

$\implies x = (1710-x)\times \frac{9}{10}$

$\implies 10x = 15390-9x$

$\implies 19x = 15390$

$\implies x = \frac{15390}{19}$

$\implies x = Rs\:810$

$ii) Selling \: price \:of \\second \: horse = 1710-x\\=1710-810\\=Rs\:900$

profit (g) = 25%,

$c.p = \frac{s.p \times 100}{100+g}\\=\frac{900 \times 100}{100+25}\\=\frac{90000}{125}\\=Rs\:720$

iii ) Total cost price of two horses = 810+720 = Rs 1530

Total selling price of two horses = Rs 1710

Total profit (p) = 1710 - 1530

= Rs 180

$Profit \: percentage \\=\frac{p \times 100}{total \c.p}\\= \frac{180\times 100}{1530}\\=11.76\%$

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