Question

A man sells two mobile phones at the same price. On one he makes a profit
of 10% and on the other he incurs a loss of 10%. Find his gain or loss
percent on the whole transaction.​

Answer 1

Answer:

0% of loss and profit

Step-by-step explanation:

Because he faced 10% of loss and 10% of profit as well so the answer will be 0

Answer 2

His loss percent on the whole transaction=10%

Step-by-step explanation:

Let x be the selling price of each mobile.

Profit on one mobile phone=10%

Loss on second mobile phone=10%

Total S.P=x+x=2x

C.P=$\frac{100}{100+proift(in\;percentage)}\time S.P$

Using the formula

C.P of one phone=$\frac{100}{100+10}\times x=\frac{100}{110}x=\frac{11}{10}x$

C.P of second phone=$\frac{100}{100-loss(in\;percentage)}\times 100=\frac{100}{100-10}\times x=\frac{10}{9}x$

Total C.P=$\frac{10}{11}x+\frac{10}{9}x=\frac{90x+110x}{90}=\frac{200}{90}x$

Total C.P=$\frac{20}{9}x$

S.P<C.P

Because

$2x<\frac{20}{9}x$

Loss=C.P-S.P=$\frac{20}{9}x-2x=\frac{20x-18x}{9}=\frac{2x}{9}$

Loss%=$\frac{loss}{C.P}\times 100$

Using the formula

Therefore,Loss%=$\frac{2x}{9\times \frac{20x}{9}}\times 100=10$%

Hence,his loss percent on the whole transaction=10%

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