Question

a Man sells two pipes at rs 12 each.he gains 20% on one and loses 20% on the other.in the whole transaction there is.​

Answer 1

Answer:

Given that

Selling price of each pipe is 12rs

sp = ((100+g)/100)* cp

sp = ((100-l)/100)* cp

Therefore cp of 1st pipe

cp1= 12*(100/120)= 10rs

cost price of second pipe

cp2= 12*(100/80) =15 rs

hence total cp is 10rs +15rs is equal to 25 rs

total sp is 24rs

hence cp is greater than selling price

therefore loss is 1rs

loss percentage = (loss/cp) *100

                            =(1/25)*100= 4%

There is direct formula for effective percentage is a%-b%+(ab/100)