Question

A man sells two tables for ₹12,480 each. On one he gains 20% and on the other, he loses 20%. How much does he gain or lose in t

Answer 1

Answer:

First method :- use formula , % loss/profit = x + y + xy/100

for loss use negative sign and profit use positive sign

Here 20% profit , x = +20 and 20% loss = -20

Now, % loss/profit = 20 - 20 + (20)(-20)/100 = -400/100 = -4%

Here negative sign shows the man's loss 4%

Let selling price of each table is 12480 Rs

Cost price , when he gains 20% = 12480/120*100= 10,400

Cost price , when he lost 20% = 12480/80 × 100 = 1560

Total cost price = 10,400+1,560= 11,960

Total loss = 11,960-2*100 =  Rs

Hence , loss % = 250/6250 × 100 = 4 %

Answer 2

Answer:

Step-by-step explanation:

Selling price of two Table sets =12480 Rs. each

Let cost price of a Table sets on which he gain 20% be X Rs  

and another Table sets on which he lost 20% be Y Rs.

Solving for Table sets on which he gain

We know that, Selling price=Cost price+profit

⇒12480=X+20% of X

⇒12480=X+0.2X

⇒12480=1.2X

⇒X=12480/1.2

∴X=10400 Rs

Now, Solving for Table sets on which he loss

We know that, Selling price=Cost price−loss

⇒12480=Y−20% of Y

⇒12480=Y−0.2Y

⇒12480=0.8Y

⇒Y=12480/0.8

∴Y=15600 Rs

Now, Total Cost price=X+Y=10400+15600=26000 Rs

and Total Selling price=2×12480=24960 Rs

Since Selling price<CostPrice

So, In whole transaction, there is a Loss of 26000−24960=Rs1040