Math, asked by vickysmn5041, 1 year ago

A man sells two tables for rupees 12480 each .on one he gains 20% and the others he loses 20%.how much does he gain or lose in the whole transaction

Answers

Answered by Anonymous
12
SP of one table=Rs.12480
Profit=20%
CP=SP*100/100+P%
=12480*100/100+20
=1248000/120
=Rs.10400
SP of another table=Rs.12480
L%=20%
CP=SP*100/100-L%
=12480*100/100-20
=1248000/80
=Rs.15600
SP of two table=12480+12480
=Rs.24960

CP of two tables=10400+15600
Rs.26000
Since CP is greater
Loss=26000-24960
=Rs.1040
Answered by wifilethbridge
7

Given: A man sells two tables for rupees 12480 each .on one he gains 20% and the others he loses 20%.

To Find: how much does he gain or lose in the whole transaction

Solution:

Case 1:

Selling price of table = Rs.12480

Gain% = 20%  

CP = \frac{SP \times 100}{100+P\%}\\CP=\frac{12480 \times 100}{100+20}=10400

Case 2:

Selling price of table = Rs.12480

Loss% = 20%  

CP = \frac{SP \times 100}{100-L\%}\\CP=\frac{12480 \times 100}{100-20}=15600

Total SP = 12480+12480=24960

Total CP = 10400+15600=26000

CP>SP

SO, Loss

Loss\% = \frac{CP-SP}{CP} \times 100\\Loss\% = \frac{26000-24960}{26000}\times 100\\Loss\% =4\%

Hence The loss% is 4%

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