A man sets his watch by a whistle that is 2 km. away how much will his watch be in error (speed of sound in air 330 m /sec
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Time delay due to time taken by sound to reach the clock
- = 2000 m/ 330 m/s = 6.06 s.
Thus his watch will be slower by 6.06 seconds.
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1
Answer:
2000÷330= 6.06 is the correct answer
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