a man sitting in a train traveling at a speed of 30 km/h notes that a train going in the opposite direction crosses homing seconds.if the lenth of these trains is 200 m the speed of the other train will be
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Rate of the travelling goods train = 50km/hr (Given)
Time taken by the goods train to travel opposite = 9sec (Given)
Length of the goods train = 187.5cm (Given)
Let the speed of the goods train be = x km/hr
Then, the relative speed = 187.5/9
Thus, using the equation -
(50+x) × (5/18) = 187.5/9
On solving -
= x = 25 km/hr
Hence, the speed of the train is 25 km/hr
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