A man sitting in an areoplane observes
that the angle of depression of two
temple 2 km a pour t are 6010. 500. If
the plane is exactly above the middle
point of the Ime joining the temple, then
find the height
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Let E and D be the two positions of the plane and A be the point of observation.
Let ABC be the horizontal line through A.
It is given that angles of elevation of the plane in two positions E and D are a point A are 60o and 30o respectively.
∠EAB=60o, ∠DAB=30o.
It is also given that EB=30003 m.
In ΔABE,tan60o=ABBE
13=AB30003
AB=3000 m
In ΔACD,tan30o=ACDC
31=AC30003
AC=9000 m
Distance =BC=AC–AB=9000–3000=6000 m
The plane travels 6 km in 30 second,
Then the speed of the plane =306000=200m/sec
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