Math, asked by bubaisove, 7 months ago

a man sitting in train which is travelling at 50 km /hr observes that a goods train, travelling opposite direction, takes 9 secoonds to pass him. if the good long. find out seed

Answers

Answered by atharvashukla2307
0

Answer:

Relative speed =280/9 m / sec = (280/9*18/5) kmph = 112 kmph.

Speed of goods train = (112 - 50) kmph = 62 kmph.

Step-by-step explanation:

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Answered by Anonymous
4

Hey buddy here is your answer.....

Let the speed of the goods train

be x km/hr.

Relativespeed =(50+x) kmhr =(50+x)×185 m/s.

Therefore, (50+x)×5/18187.5=9.

⇒250+5x187.5×18=9

⇒250+5x=187.5×2=375

⇒250+5x=187.5×2=375⇒5x=375−250=125

⇒250+5x=187.5×2=375⇒5x=375−250=125⇒x=25 km/hr.

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