a man sold 12 candies in 10$ had loss of b% then again sold 12 candies at 12$ had profit of b% find the value of b.
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Let the CP be 'x' then:
(x-10)*100/x = b% ----------->1
(12- x) * 100 /x = b% ------->2
(x-10)*100 / x = (12-x)*100 / x
x-10 = 12-x
x = 11
So by Submitting value of x into one of above question (1 or 2) we get b
which is 9.09 or 9 Approx
(x-10)*100/x = b% ----------->1
(12- x) * 100 /x = b% ------->2
(x-10)*100 / x = (12-x)*100 / x
x-10 = 12-x
x = 11
So by Submitting value of x into one of above question (1 or 2) we get b
which is 9.09 or 9 Approx
Answered by
0
A man sold 12 candies in 10$ had loss of b% then again sold 12 candies at 12$ had profit of b%, the value of b is 9.09.
Given,
candles = 12
Selling prize 1 = $10 with b% loss
Selling prize 2 = $12 with b% profit
To find,
b = ?
Solution,
Let the cost prize be 'x'.
% Loss =
% Profit =
Since, we have value of x, lets substitute it in equation.
Therefore, the value of b is 9.09%.
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